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100a^2+5=9
We move all terms to the left:
100a^2+5-(9)=0
We add all the numbers together, and all the variables
100a^2-4=0
a = 100; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·100·(-4)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*100}=\frac{-40}{200} =-1/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*100}=\frac{40}{200} =1/5 $
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